Page 71 - Calculating Agriculture Cover 20191124 STUDENT - A
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CH 5] Calculating Agriculture 5-9
7) Bring down the next period of 00 to the right of the decimal. Then multiply 16
x 20 = 320. Follow this process to its conclusion.
1 6 . 1 5 5 4
√ 2 61 . 00 00 00 00
1 x 1 = 1
20 x 1 = 20 1 61
20 + 6 = 26 x 6 = 1 56
320 goes into 500 one time. Add 1 to 320 = 321. Multiply 321 x 1 = 321
20 x 16 = 320 5 00 and place under 500. Subtract 500 – 321 = 179.
320 + 1 = 321 x 1 = 3 21 Bring down the next period 00 to 179. Multiply 161 x 20 = 3220. 3220 goes into
17900 five times. Add 5 to 3220 = 3225 and multiply by 5. Place the quotient
20 x 161 = 3220 1 79 00 3225 x 5 = 16125 under 17900 and subtract. 17900—16125 = 1775. Bring
3220 + 5 = 3225 x 5 = 1 61 25 down the next period (00) to 177500.
20 x 1615 = 32300 17 75 00 Multiply 1615 x 20 = 32300. 32300 goes into 177500 five times. Add 5 +
32300 = 32305. Multiply 5 x 32305 = 161525, and place that value under
32300 + 5 = 32305 x 5 = 16 15 25 177500. Subtract 177500—161525 = 15975. Bring down the next period
(00) to 1597500.
20 x 16155 = 323100 1 59 75 00
323100 + 4 = 323104 x 4 = 1 29 24 16 Multiply 16155 x 20 = 323100. 323100 goes into 1597500 4 times. Add 4 +
323100 = 323104. Multiply 4 x 323104 = 1292416. Place 1292416 below
30 50 84 1597500 and subtract to yield 305084. As this calculation has taken us to the
10thousands decimal round to the thousandths and the result is 16.155, thus
verifying the calculator answer with the algorithm.
Now, you have a skill that not many people have in that you calculated the
square root of a number using the square root algorithm. Let’s go through another
example for your practice on a step by step process.
Example B: Calculate the square root of 673.8 to the nearest tenth.
Solution algorithm:
1) Place the decimal point directly over the decimal point in the number. 5
.
√ 673.8 = √ 673 . 8
2) Beginning at the decimal point, separate the numbers into groups of two
figures each, called periods. If there are any numbers to the right of the
decimal, group them into periods also. If zeros are needed after the
decimal, add them so as to make groups of two figures. A bar may be
placed over the periods.
. .
√ 673 . 8 = √ 6 73 . 80 00
3) Determine the largest perfect square contained in the left-hand period, 6.
As 2 x 2 = 4, this value is largest number whose product is contained in
the period 6. Place 2 above the 6 in the statement. Since 2 x 2 = 4 this
product is placed below the 6 and is to be subtracted from it to determine
the remainder.
2 .
√ 6 73 . 80 00
2 x 2 = 4 4
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