Page 73 - Calculating Agriculture Cover 20191124 STUDENT - A

CH 5] Calculating Agriculture 5-11

Get a alone on the left side of the equation requires the square root of
2
2
c − b be calculated.
2
c = 34 ft. c = 34 x 34 = 1,156
2
b = 30 ft. b = 30 x 30 = 900

2
2
B) Substitute the calculated values for c – b into the equation:

2
c 2 — b 2 = a
1,156 — 900 = 256.

2
a = 256, now calculate the square root (√) of 256.

1) Place the decimal point directly over the decimal point in the number.
.
√ 256. = √ 256 .

2) Beginning at the decimal point, separate the numbers into groups of two
figures each, called periods. If there are any numbers to the right of the
decimal, group them into periods also. If zeros are needed after the decimal,
add them so as to make groups of two figures. A bar may be placed over the
periods.
.
√ 256. = √ 2 56 . 00 00

. .
√ 256 . = √ 2 56 . 00

3) Determine the largest perfect square contained in the left-hand period, 2. As 1
x 1 =1, this value is not larger than the left-hand period of 2. Write 1 above
the first period in our number (2) and write 1 under the 2 in the first period
on the left. This is the first figure of the answer.
5
1 .
√ 2 56 . 00
1 x 1 = 1

4) Subtract the largest perfect square (1) from the first period (2). Bring down the
next period (56) to the remainder to form the trial dividend.

1 .
√ 2 56 . 00
1 x 1 = 1 1
1 56

5) Multiply the first number of the answer (1) by 20 to obtain the trial divisor
(20). Write this number as indicated.

1 .
√ 2 56 . 00
1 x 1 = 1 1
20 x 1 = 20 1 56

What did the square say to the old circle? Been around long?

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