Page 72 - Calculating Agriculture Cover 20191124 STUDENT - A

5-10 Measurements CH 5]

4) Subtract the largest perfect square (4) from the first period (6). This
calculation yields (6 – 4 =) 2. Bring down the next period (73) to the
remainder to form the trial dividend.

2 .
√ 6 73 . 80 00
2 x 2 = 4 4
2 73

5) Multiply the first number of the answer (2) by 20 to obtain the trial divisor
(40). Write this number as indicated. Divide the trial divisor 40 into the
remainder 273. We determine that 273 divided by 40 = 6.825. Adding 6 to
40 and the resulting trial divisor becomes 46; 46 x 6 = 276 which is larger
than 273, so 6 is not used. Try 5 added to 40 and the summation is 45
which is considered as a trial divisor; 45 x 5 = 225, which is less than 273.
Now we have the second digit in our calculation, 5. The product of 5 x 45
= 225 which is subtracted from the value 273 to yield a remainder of 48.
5
2 6 .
√ 6 73 . 80 00
2 x 2 = 4 4
20 x 2 = 40 2 73
40 + 6 = 46 too large
40 + 5 = 45 x 5 = 2 25
48

6) Bring down the next period of 80 to the right of the decimal. Then multiply
20 x 25 =500. Follow this process to its conclusion.
2 5 . 9 5 Rounded to 26.0
√ 6 73 . 80 00
2 x 2 = 4 4
20 x 2 = 40 2 73
40 + 6 = 46 too large Bring down the next period 80 to 48. Multiply 25 x 20 = 500. 500 goes into
4880 nine times. Add 9 to 500 = 509 and multiply by 9. Place the quotient 509
40 + 5 = 45 x 5 = 2 25 x 9 = 4581 under 4880 and subtract. 4880 — 4581 = 299. Bring down the next
period (00) to 299 which now becomes 29900.
20 x 25 = 500 48 80
500 + 9 = 509 x 9 = 45 81 Multiply 259 x 20 = 5180. 5180 goes into 29900 five times. Add 5 + 5180 =
20 x 259 = 5180 2 99 00 5185. Multiply 5 x 5185 = 25925, and place that value under 29000.
Subtract 29000 — 25925 = 3975. As this calculation has taken us to the
5180 + 5 = 5185 x 5 = 2 59 25 hundredth as 25.95; the problem asks to round the number to the nearest
tenth. Rounding 25.95 to the nearest tenth yields a value of 26.0.
39 75

Answer: Calculate the square root of 673.8 to the nearest tenth yields the
square root rounded as 26.0.

Let’s take your skill with square root in a different direction and use it in a
problem to calculate the length of one side of triangle. In this example the step by
step algorithm will be demonstrated.

Example C A ladder (c) 34 feet long leans against the side of a building
reaching a point on the building 30 feet above the ground
(b). Calculate the length of the base (a) for this triangle to 34’ b
2
2
2
the nearest 10 using the equation a + b = c
th
c 30’
Solution algorithm:

2
2
2
2
A) Rewrite this equation, a + b = c , to solve for a : a

2
2
2
a = c – b ?
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