Page 166 - Calculating Agriculture Cover 20191124 STUDENT - A
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14-26                               Feeds and Feeding                                CH 14]



              Calculating the amount of feed needed for animals.

                  There are a number of factors that affect the feeding of animals. Animal feeders, when planning
              (budgeting) the requirements of feed for the animals they will be feeding, estimate the pounds of
              feed, or tons of feed, or hundred weight (Cwt) of feed that they will need to feed their animals for
              market. Their budgeting (planning) is based on their record keeping and history of feeding for pounds
              of gain, given the rations that will be prepared. Knowing the feed conversion ratios allows the animal
              feeder to estimate the feed they will need.

              Example      Presume a feeding regimen for 250 pigs and that each pig will gain on average 35
                           pounds to reach slaughter weight. With a feed conversion of 3.8 : 1, (a) how much
                           feed will each pig consume to gain 35 pounds? (b) How many pounds of feed will be
                           required for 250 pigs? (c) How many hundred weight (Cwt) will be planned? (d) How
                           many tons will be purchased?

              Solution

                    (a)  Feed consumed for gain  =  Pounds to be gained  x   feed required per pound of gain
                                            =     35  pounds      x           3.8 pounds
                    (a)  Feed consumed for gain =  133 lbs per pig

                    (b)  Total pounds required  =   # of animals fed  x   Feed consumed per animal
                                            =   250 hd          x    133 # / hd
                    (b)  Total pounds required  =   33,250 #

                    (c)    Cwt of feed      =   33,250 #        ÷    100 # / Cwt
                                            =   33,250 #        ÷    100 # / Cwt
                    (c)       Cwt of feed   =   332.50 Cwt

                    (d)   Tons of feed      =   33,250 #        ÷    2,000 # / ton
                                            =   33,250 #        ÷    2,000 # / ton
                    (d)   Tons of feed      =   16.125 tons


              Feeding efficiency — Dairy Cattle and milk production
                     Dairy cows consume dry hay, silage, pasture and grain
              during lactation to produce milk. Feeding efficiency can then be
              calculated on each of these elements to their diet, though the
              pounds of milk produced is very dependent on their breed. The
              measurement can also be made on the pounds of butter fat that
              cows produce.  Figure 14.11 indicates the ratio of milk to grain.
              If a cow is producing 12,000 pounds of milk per year, then its
              grain intake will have a ratio of 3 pounds of milk for each pound
              of grain fed. Remember, a dairy cow consumes hays, pasture and
              water to produce milk. The values in Figure 14.11 are derived
              from feeding grain rations (concentrate rations) to a lactating
              cow.
                  Though the traditional individual feeding of lactating cows
              in stanchioned barns or milking parlors is still used, the new
              methods include challenge feeding lactating cows based on their
              individual total milk production and butterfat content, measured
              as the cow is being milked. This allows for a more economical
              way of feeding individual cows based on their production.
                  Phase Feeding.  Our Agriculture Researchers recommend that the lactation of a cow be divided
              into four periods or phases, each requiring a different type of feeding program.
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